number 1 2 3 4 5

Package com; public class test {public static void main (string [] ARGs) {system. out. println (getsteps1 (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>>"); system. out. println (test. getsteps (); system. out. println (">>>>>>>>>>>>>>>>>>>>>

It is not very difficult to see an algorithm question on the Internet. There are also solutions for searching, but there are usually several layers of for loops. I tried to write it down. /*** Give you a set of strings such as {5, 2, 3, 2, 4, 5,},

Compile a function. When n is an even number, call the function to calculate 1/2 + 1/4 +... + 1/n. When n is an odd number, call the function 1/1 + 1/3 +... + 1/n ., Even number First, write a function whose n is an even number: Def peven (n): s =

Regular Expression of phone number (mobile phone number, 3-4 area code, 7-8 live video number, 1-4 extension code) (\ D {11}) | ^ (\ d {7, 8}) | (\ d {4} | \ d {3})-(\ d {7, 8 }) | (\ d {4} | \ d {3})-(\ d {7, 8 }) -(\ d {4} | \ d {3} | \ d {2} | \

As early as itpub saw a SQL expert, like the puzzle, the following is a puzzle. I tried SQL Server to resolve this issue.With 1 points,5 points , 10 points , 25 points , 50 cents coins into one yuan, a total of several combinations of methods?

To get this topic, we will first think of using loops to complete.But not every operator is a "+" sign.Therefore, we are here to use (-1) of the I-side to do "+" "-" number control.The loop variable i is then treated as the denominator.Here we have

Package COM. WZS; // Add difficulty to the first question. Use the numbers 1, 2, 3, 4, and 5 to write a main function in Java and print out all the different orders, // For example, 51234, 12345, etc., the requirement: "4" cannot be In the third

#include int main () {double sum;     int i;          for (sum=0,i=1;iBe careful to define its type, divide it into two parts, and define it as "I" to see if the denominator is an odd or even number, and the sum is summed. C language: Calculate 1/1-1

Title: "AABABCABCDABCDE", obtaining the number of occurrences of each letter in a string results: A (5) B (4) C (3) d (2) e (1)At first may not be able to do this problem, and now step into the analysis1: First it is a string, but to analyze each

47. Innovation workshop (algorithm ):Returns the longest descending subsequence of an array, for example, {9, 4, 3, 2, 5, 3, 2,4,3, 2}   Idea: Dynamic Planning Calculates the longest descending subsequence of the sequence of the current number. Each